Oracle-L: SQL HELP!!!

From: Viktor <stant_98_at_yahoo.com>
Date: Tue, 26 Aug 2003 12:59:35 -0800
Message-ID: <F001.005CD51D.20030826125935@fatcity.com>

Hello,

I was wondering if someone can help me with a report. I am stuck figuring out what I can do to complete it. Here is what I need to do:

for a given date range, i..e. start_date - end_date ('01/01/2003', '12/31/2003'), I need to count all "web", and "non-web" records. If seq_no > 4000, then it's web, otherwise non-web. seq_no is not unique. So it's like 2 different where claused in a single select. Could I somehow use CASE or decode to accomplish this. Here is what I am trying to do in select:

select id ,

          to_char(received_date, 'YYYY-mm'),
          id||yr||seq_no||ck MSNO
          CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end Count_WEB,
          CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0   END  HARDCOPY

from t
where received_date between '01/01/2003' and '12/31/2003' group by id,

   to_char(received_date, 'YYYY-mm'),
   sequence_no,
   id||yr||seq_no||ck
/

AR 2003-01 AR030023T         0              1
AR 2003-01 AR0200302         0              1
AR 2003-01 AR020047K         0              1
AR 2003-01 AR020077N         0              1

I would like to show Year-Month once and count all instances of id||yr||seq_no||ck (primary_key) for that Year-Month, but not to break on it, and unfortunaley it won't let me do it without grouping on seq_no

Please advise!!!

Any help is greatly appreciated!

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Author: Viktor
INET: stant_98_at_yahoo.com

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