Re: SQL HELP!!!

From: Viktor <stant_98_at_yahoo.com>
Date: Tue, 26 Aug 2003 14:54:26 -0800
Message-ID: <F001.005CD54F.20030826145426@fatcity.com>

Dave,  

Thanks much! I appreciate your help. One other thing I might have forgotten is there a way to calculate non_web_count - to - total % and web_count - to total %  

so in this way:  

output would be like:
ID YEAR NON WEB % WEB %NON-WEB  

AC 2003-01            47        98       67.6        32.4
AC 2003-02            26       112
AC 2003-03            57       121
AC 2003-04            40       124
 

And so forth...  

Thanks Dave and evryone else for your help!

Dave Hau <davehau123_at_netscape.net> wrote: select id, received_date,
count(count_non_web) non_web_count,
count(count_web) web_count
from

(select id, to_char(received_date, 'YYYY-mm') received_date,
(case when seq_no <= 4000 then 1 else null end) count_non_web,
(case_when seq_no > 4000 then 1 else null end) count_web

from t
where received_date between '01/01/2003' and '12/31/2003') group by id,
received_date

HTH,
Dave

stant_98_at_yahoo.com wrote:
> Jared,
>
> Thanks for your fast reply! Sorry if I didn't explain myself clear
> enough. Unfortunately count_web is not a column, id||yr||seq_no||ck is a
> combination of 4 columns that make up a primary key. if seq_no >4000, in
> a id||yr||seq_no||ck row, it's a "web row", if not then it's not. what I
> would like to see is:
>
> ID Received_date Non-web count Web_count
> AR 2003-01 0 4
> AR 2003-02 0 6
> AR 2003-0 1 8
> and so forth.....
>
> Again thanks for any suggestions you may have!
>
> Thanks very much!
>
>
>
>
>
>
>
> Jared.Still_at_radisys.com wrote:
>
>
> I'm not sure I entirely understand the result you are trying to
> achieve.
>
> Perhaps this will help
>
> select received_date, msno, sum(count_web), hardcopy
> from (
> select id ,
> to_char(received_date, 'YYYY-mm') received_date,
> id||yr||seq_no||ck MSNO
> CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end
> Count_WEB,
> CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0 END
> HARDCOPY
> from t
> where received_date between '01/01/2003' and '12/31/2003'
> group by id,
> &nbs! p; to_char(received_date, 'YYYY-mm'),
> sequence_no,
> id||yr||seq_no||ck
> )
> group by received_date, msno, hardcopy
> /
>
>
>
>
> Viktor
> Sent by: ml-errors_at_fatcity.com
>
> 08/26/2003 01:59 PM
> Please respond to ORACLE-L
>
>
> To: Multiple recipients of list ORACLE-L
>
> cc:
> Subject: SQL HELP!!!
>
>
>
>
> Hello,
>
> I was wondering if someone can help me with a report. I am stuck
> figuring out what I can do to complete it. Here is what I need to do:
>
> for a given date range, i..e. start_date - end_date ('01/01/2003',
> '12/31/2003'), I need to count all "web", and "non-web" reco! rds.
> If seq_no > 4000, then it's web, otherwise non-web. seq_no is not
> unique. So it's like 2 different where claused in a single select.
> Could I somehow use CASE or decode to accomplish this. Here is what
> I am trying to do in select:
>
> select id ,
> to_char(received_date, 'YYYY-mm'),
> id||yr||seq_no||ck MSNO
> CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end
> Count_WEB,
> CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0 END
> HARDCOPY
> from t
> where received_date between '01/01/2003' and '12/31/2003'
> group by id,
> to_char(received_date, 'YYYY-mm'),
> sequence_no,
> id||yr||seq_no||ck !
> /
>
> AR 2003-01 AR030023T 0 1
> AR 2003-01 AR0200302 0 1
> AR 2003-01 AR020047K 0 1
> AR 2003-01 AR020077N 0 1
>
> I would like to show Year-Month once and count all instances of
> id||yr||seq_no||ck (primary_key) for that Year-Month, but not to
> break on it, and unfortunaley it won't let me do it without grouping
> on seq_no
>
> Please advise!!!
> Any help is greatly appreciated!
>
>
>
> ------------------------------------------------------------------------
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-- 
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-- 
Author: Dave Hau
INET: davehau123_at_netscape.net

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-- 
Author: Viktor
  INET: stant_98_at_yahoo.com

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Received on Tue Aug 26 2003 - 17:54:26 CDT