RE: SQL HELP!!!

From: Jamadagni, Rajendra <Rajendra.Jamadagni_at_espn.com>
Date: Tue, 26 Aug 2003 17:14:26 -0800
Message-ID: <F001.005CD578.20030826171426@fatcity.com>

Try something like ...    

select id, col_1, col_2,sum(web_c),sum(other_c) from
(select id, to_char(received_date,'YYYY-MM') col_1,yr||seq_no||ck col_2,

       case when seq_no > 4000 then 1 else 0 end web_c,
       case when seq_no <= 4000 then 1 else 0 end other_c 

  from t
 where received_date between your_start_date and your_end_date) group by id, col_1, col_2
/  

Raj

---

---

Rajendra dot Jamadagni at nospamespn dot com All Views expressed in this email are strictly personal. QOTD: Any clod can have facts, having an opinion is an art !

-----Original Message-----
Sent: Tuesday, August 26, 2003 5:00 PM
To: Multiple recipients of list ORACLE-L

Hello,  

I was wondering if someone can help me with a report. I am stuck figuring out what I can do to complete it. Here is what I need to do:  

for a given date range, i..e. start_date - end_date ('01/01/2003', '12/31/2003'), I need to count all "web", and "non-web" records. If seq_no > 4000, then it's web, otherwise non-web. seq_no is not unique. So it's like 2 different where claused in a single select. Could I somehow use CASE or decode to accomplish this. Here is what I am trying to do in select:  

select id ,

          to_char(received_date, 'YYYY-mm'),
          id||yr||seq_no||ck MSNO
          CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end Count_WEB,
          CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0   END  HARDCOPY

 from t
where received_date between '01/01/2003' and '12/31/2003' group by id,

   to_char(received_date, 'YYYY-mm'),
   sequence_no,
   id||yr||seq_no||ck
/  

AR 2003-01 AR030023T         0              1
AR 2003-01 AR0200302         0              1
AR 2003-01 AR020047K         0              1
AR 2003-01 AR020077N         0              1

 

I would like to show Year-Month once and count all instances of id||yr||seq_no||ck (primary_key) for that Year-Month, but not to break on it, and unfortunaley it won't let me do it without grouping on seq_no  

Please advise!!!  

Any help is greatly appreciated!    

---

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Author: Jamadagni, Rajendra
  INET: Rajendra.Jamadagni_at_espn.com

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Received on Tue Aug 26 2003 - 20:14:26 CDT