Oracle FAQ Your Portal to the Oracle Knowledge Grid
HOME | ASK QUESTION | ADD INFO | SEARCH | E-MAIL US
 

Home -> Community -> Mailing Lists -> Oracle-L -> Re: SQL HELP!!!

Re: SQL HELP!!!

From: <Jared.Still_at_radisys.com>
Date: Tue, 26 Aug 2003 14:24:26 -0800
Message-ID: <F001.005CD542.20030826142426@fatcity.com>


Viktor,

By using an inline view, count_web does indeed become a column.

Did you try the query?

Jared

Viktor <stant_98_at_yahoo.com>
 08/26/2003 01:29 PM  

        To:     Jared.Still_at_radisys.com, ORACLE-L_at_fatcity.com
        cc: 
        Subject:        Re: SQL HELP!!!


Jared,  

Thanks for your fast reply! Sorry if I didn't explain myself clear enough. Unfortunately count_web is not a column, id||yr||seq_no||ck is a combination of 4 columns that make up a primary key. if seq_no >4000, in a id||yr||seq_no||ck row, it's a "web row", if not then it's not. what I would like to see is:  

ID  Received_date   Non-web count       Web_count
AR 2003-01            0                           4
AR 2003-02            0                           6
AR 2003-0              1                           8
and so forth.....  

Again thanks for any suggestions you may have!  

Thanks very much!    

Jared.Still_at_radisys.com wrote:

I'm not sure I entirely understand the result you are trying to achieve.

Perhaps this will help

select received_date, msno, sum(count_web), hardcopy from (
select id ,

         to_char(received_date, 'YYYY-mm') received_date,
         id||yr||seq_no||ck MSNO
         CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end Count_WEB,
         CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0   END  HARDCOPY 

 from t
where received_date between '01/01/2003' and '12/31/2003' group by id,
  ; to_char(received_date, 'YYYY-mm'),
   sequence_no,
  id||yr||seq_no||ck
)
group by received_date, msno, hardcopy
/

Viktor <stant_98_at_yahoo.com>
Sent by: ml-errors_at_fatcity.com
 08/26/2003 01:59 PM
 Please respond to ORACLE-L

        
        To:        Multiple recipients of list ORACLE-L 
<ORACLE-L_at_fatcity.com> 
        cc:         
        Subject:        SQL HELP!!!



Hello,  

I was wondering if someone can help me with a report. I am stuck figuring out what I can do to complete it. Here is what I need to do:  

for a given date range, i..e. start_date - end_date ('01/01/2003', '12/31/2003'), I need to count all "web", and "non-web" recor ds. If seq_no > 4000, then it's web, otherwise non-web. seq_no is not unique. So it's like 2 different where claused in a single select. Could I somehow use CASE or decode to accomplish this. Here is what I am trying to do in select:  

select id ,

         to_char(received_date, 'YYYY-mm'),
         id||yr||seq_no||ck MSNO
         CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end Count_WEB,
         CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0   END  HARDCOPY 

 from t
where received_date between '01/01/2003' and '12/31/2003' group by id,
  to_char(received_date, 'YYYY-mm'),
   sequence_no,
  id||yr||seq_no||ck < BR>/  

AR 2003-01 AR030023T         0              1
AR 2003-01 AR0200302         0              1
AR 2003-01 AR020047K         0              1
AR 2003-01 AR020077N         0              1 
 

I would like to show Year-Month once and count all instances of id||yr||seq_no||ck (primary_key) for that Year-Month, but not to break on it, and unfortunaley it won't let me do it without grouping on seq_no  

Please advise!!!  

Any help is greatly appreciated!    

Do you Yahoo!?
Yahoo! SiteBuilder - Free, easy-to-use web site design software Do you Yahoo!?
Yahoo! SiteBuilder - Free, easy-to-use web site design software

--

Please see the official ORACLE-L FAQ: http://www.orafaq.net
--

Author:
  INET: Jared.Still_at_radisys.com

Fat City Network Services    -- 858-538-5051 http://www.fatcity.com
San Diego, California        -- Mailing list and web hosting services
---------------------------------------------------------------------
To REMOVE yourself from this mailing list, send an E-Mail message to: ListGuru_at_fatcity.com (note EXACT spelling of 'ListGuru') and in the message BODY, include a line containing: UNSUB ORACLE-L (or the name of mailing list you want to be removed from). You may also send the HELP command for other information (like subscribing). Received on Tue Aug 26 2003 - 17:24:26 CDT

Original text of this message

HOME | ASK QUESTION | ADD INFO | SEARCH | E-MAIL US