Re: SQL question

From: Reza Shahpori <rshahpo_at_telusvelocity.net>
Date: 1998/06/09
Message-ID: <357DF753.52A19A5E_at_telusvelocity.net>#1/1

This should also work:

SELECT * from friend
WHERE name NOT IN (SELECT name

                                        FROM    customer);

>
Received on Tue Jun 09 1998 - 00:00:00 CEST

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