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Sql query

From: Santosh Varma <vsantosh_at_psi.soft.net>
Date: Thu, 03 Oct 2002 01:23:24 -0800
Message-ID: <F001.004DEFDA.20021003012324@fatcity.com>


cannot perform an aggregate function on an expression containing an

aggregate or subquery

is the error i am getting while i am executing the query.

SELECT name

FROM (SELECT c.name, COUNT(p.clientid) p_count

FROM client c, project p

WHERE c.clientid = p.clientid

GROUP BY c.name) a,

(SELECT MAX(COUNT(clientid)) p_max

FROM project

GROUP BY clientid) b

WHERE a.p_count = b.p_max

clientid and name are the columns in client table

and projectid and clientid are the columns in project table.

santosh

-----Original Message-----

Ignaszak

Sent: Monday, September 30, 2002 6:09 PM

To: Multiple recipients of list ORACLE-L

try it:

select

name

from

(select c.name, count(p.id) p_count from clients c, projects p

where c.id = p.cl_id

group by c.name) a,

(select max(count(id)) p_max from projects

group by cl_id) b

where a.p_count = b.p_max

Regards,

Leszek

At 03:23 2002-09-30 -0800, you wrote:

>Hello all,

>

> I have a query ->

>i have 2 tables -> client and project

>

>fields in project table -> clientid/projectid

>fields in client table -> clientid/name

>

>i want to get the maximum orders one client has got. i mean a project

>having the greatest clients

>how to write it in single query ??

>

>

>like

>project 1 client 1

>project 2 client 1

>project 3 client 2

>

>in the above case, the query should return client ( 1 ).

>

>Thanks and regards,

>Santosh

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--

Author: Leszek Ignaszak

INET: leszek.ignaszak_at_post.pl

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Author: Santosh Varma

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-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.com
-- 
Author: Santosh Varma
  INET: vsantosh_at_psi.soft.net

Fat City Network Services    -- 858-538-5051 http://www.fatcity.com
San Diego, California        -- Mailing list and web hosting services
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Received on Thu Oct 03 2002 - 04:23:24 CDT

Original text of this message

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