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RE: Sql query

From: Thomas, Kevin <Kevin.Thomas_at_calanais.com>
Date: Fri, 04 Oct 2002 07:13:27 -0800
Message-ID: <F001.004E0B91.20021004071327@fatcity.com>


HELP! -----Original Message-----
Sent: 04 October 2002 14:53
To: Multiple recipients of list ORACLE-L

sql server 7???  

and you are trying to find an answer on Oracle board?  

Igor Neyman, OCP DBA
ineyman_at_perceptron.com <mailto:ineyman_at_perceptron.com>   

 Hi naveen,

cannot perform an aggregate function on an expression containing an aggregate or subquery

is the error i am getting while i am executing the query. i am executing this query in sql server 7

santosh

-----Original Message-----
[mailto:root_at_fatcity.com]On Behalf Of Naveen Nahata Sent: Thursday, October 03, 2002 9:03 PM To: Multiple recipients of list ORACLE-L

Santosh,  

your query is working. See below  

SQL> CREATE TABLE CLIENT (
  2 CLIENTID NUMBER PRIMARY KEY,
  3 NAME VARCHAR2(10)
  4 );  

Table created.  

SQL> CREATE TABLE PROJECT(
  2 PROJECTID NUMBER PRIMARY KEY,
  3 NAME VARCHAR2(10),
  4 CLIENTID REFERENCES CLIENT(CLIENTID)   5 );  

Table created.  

SQL> insert into client values(1, 'Naveen');  

1 row created.  

SQL> insert into client values(2, 'Santosh');  

1 row created.  

SQL> insert into project values(1, 'Oracle', 1);  

1 row created.  

SQL> insert into project values(2, 'Java', 1);  

1 row created.  

SQL> insert into project values(3, 'SQL', 2);  

1 row created.  

SQL> commit;  

Commit complete.  

SQL> ed
Wrote file afiedt.buf  

  1 SELECT name
  2 FROM (SELECT c.name, COUNT(p.clientid) p_count   3 FROM client c, project p
  4 WHERE c.clientid = p.clientid
  5 GROUP BY c.name) a,
  6 (SELECT MAX(COUNT(clientid)) p_max
  7 FROM project
  8 GROUP BY clientid) b
  9* WHERE a.p_count = b.p_max
SQL> /   NAME



Naveen  

SQL> I can run your query, then what's the problem? SQL>   Regards
Naveen

-----Original Message-----
Sent: Thursday, October 03, 2002 2:53 PM To: Multiple recipients of list ORACLE-L

cannot perform an aggregate function on an expression containing an

aggregate or subquery

is the error i am getting while i am executing the query.

SELECT name

FROM (SELECT c.name, COUNT(p.clientid) p_count

FROM client c, project p

WHERE c.clientid = p.clientid

GROUP BY c.name) a,

(SELECT MAX(COUNT(clientid)) p_max

FROM project

GROUP BY clientid) b

WHERE a.p_count = b.p_max

clientid and name are the columns in client table

and projectid and clientid are the columns in project table.

santosh

-----Original Message-----

Ignaszak

Sent: Monday, September 30, 2002 6:09 PM

To: Multiple recipients of list ORACLE-L  

try it:

select

name

from

(select c.name, count(p.id) p_count from clients c, projects p

where c.id = p.cl_id

group by c.name) a,

(select max(count(id)) p_max from projects

group by cl_id) b

where a.p_count = b.p_max

Regards,

Leszek

At 03:23 2002-09-30 -0800, you wrote:

>Hello all,

>

> I have a query ->

>i have 2 tables -> client and project

>

>fields in project table -> clientid/projectid

>fields in client table -> clientid/name

>

>i want to get the maximum orders one client has got. i mean a project

>having the greatest clients

>how to write it in single query ??

>

>

>like

>project 1 client 1

>project 2 client 1

>project 3 client 2

>

>in the above case, the query should return client ( 1 ).

>

>Thanks and regards,

>Santosh

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--

Author: Leszek Ignaszak

INET: leszek.ignaszak_at_post.pl

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Author: Santosh Varma

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Author: Thomas, Kevin
  INET: Kevin.Thomas_at_calanais.com

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Received on Fri Oct 04 2002 - 10:13:27 CDT

Original text of this message

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