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RE: Sql query

From: Santosh Varma <vsantosh_at_psi.soft.net>
Date: Thu, 03 Oct 2002 22:23:30 -0800
Message-ID: <F001.004E05F0.20021003222330@fatcity.com>


 Hi naveen,
cannot perform an aggregate function on an expression containing an aggregate or subquery

is the error i am getting while i am executing the query. i am executing this query in sql server 7

santosh

  -----Original Message-----
  From: root_at_fatcity.com [mailto:root_at_fatcity.com]On Behalf Of Naveen Nahata   Sent: Thursday, October 03, 2002 9:03 PM   To: Multiple recipients of list ORACLE-L   Subject: RE: Sql query

  Santosh,

  your query is working. See below

  SQL> CREATE TABLE CLIENT (
    2 CLIENTID NUMBER PRIMARY KEY,
    3 NAME VARCHAR2(10)
    4 );

  Table created.

  SQL> CREATE TABLE PROJECT(
    2 PROJECTID NUMBER PRIMARY KEY,
    3 NAME VARCHAR2(10),
    4 CLIENTID REFERENCES CLIENT(CLIENTID)     5 );

  Table created.

  SQL> insert into client values(1, 'Naveen');

  1 row created.

  SQL> insert into client values(2, 'Santosh');

  1 row created.

  SQL> insert into project values(1, 'Oracle', 1);

  1 row created.

  SQL> insert into project values(2, 'Java', 1);

  1 row created.

  SQL> insert into project values(3, 'SQL', 2);

  1 row created.

  SQL> commit;

  Commit complete.

  SQL> ed
  Wrote file afiedt.buf

    1 SELECT name
    2 FROM (SELECT c.name, COUNT(p.clientid) p_count     3 FROM client c, project p
    4 WHERE c.clientid = p.clientid
    5 GROUP BY c.name) a,
    6 (SELECT MAX(COUNT(clientid)) p_max     7 FROM project
    8 GROUP BY clientid) b
    9* WHERE a.p_count = b.p_max
  SQL> /   NAME



  Naveen

  SQL> I can run your query, then what's the problem?   SQL>   Regards
  Naveen
    -----Original Message-----
    From: Santosh Varma [mailto:vsantosh_at_psi.soft.net]     Sent: Thursday, October 03, 2002 2:53 PM     To: Multiple recipients of list ORACLE-L     Subject: Sql query

    cannot perform an aggregate function on an expression containing an

    aggregate or subquery

    is the error i am getting while i am executing the query.

    SELECT name

    FROM (SELECT c.name, COUNT(p.clientid) p_count

    FROM client c, project p

    WHERE c.clientid = p.clientid

    GROUP BY c.name) a,

    (SELECT MAX(COUNT(clientid)) p_max

    FROM project

    GROUP BY clientid) b

    WHERE a.p_count = b.p_max

    clientid and name are the columns in client table

    and projectid and clientid are the columns in project table.

    santosh

    -----Original Message-----

    Ignaszak

    Sent: Monday, September 30, 2002 6:09 PM

    To: Multiple recipients of list ORACLE-L

    try it:

    select

    name

    from

    (select c.name, count(p.id) p_count from clients c, projects p

    where c.id = p.cl_id

    group by c.name) a,

    (select max(count(id)) p_max from projects

    group by cl_id) b

    where a.p_count = b.p_max

    Regards,

    Leszek

    At 03:23 2002-09-30 -0800, you wrote:

>Hello all,

>

> I have a query ->

>i have 2 tables -> client and project

>

>fields in project table -> clientid/projectid

>fields in client table -> clientid/name

>

>i want to get the maximum orders one client has got. i mean a project

>having the greatest clients

>how to write it in single query ??

>

>

>like

>project 1 client 1

>project 2 client 1

>project 3 client 2

>

>in the above case, the query should return client ( 1 ).

>

>Thanks and regards,

>Santosh

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    --

    Author: Leszek Ignaszak

    INET: leszek.ignaszak_at_post.pl

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    Author: Santosh Varma

    INET: vsantosh_at_psi.soft.net

    Fat City Network Services -- 858-538-5051 http://www.fatcity.com

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    (or the name of mailing list you want to be removed from). You may

    also send the HELP command for other information (like subscribing).

-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.com
-- 
Author: Santosh Varma
  INET: vsantosh_at_psi.soft.net

Fat City Network Services    -- 858-538-5051 http://www.fatcity.com
San Diego, California        -- Mailing list and web hosting services
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Received on Fri Oct 04 2002 - 01:23:30 CDT

Original text of this message

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