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Home -> Community -> Mailing Lists -> Oracle-L -> Re: Sql query
sql server 7???
and you are trying to find an answer on Oracle board?
Igor Neyman, OCP DBA
ineyman_at_perceptron.com
Hi naveen,
cannot perform an aggregate function on an expression containing an aggregate or subquery
is the error i am getting while i am executing the query. i am executing this query in sql server 7
santosh
-----Original Message-----
From: root_at_fatcity.com [mailto:root_at_fatcity.com]On Behalf Of Naveen Nahata
Sent: Thursday, October 03, 2002 9:03 PM
To: Multiple recipients of list ORACLE-L
Subject: RE: Sql query
Santosh,
your query is working. See below
SQL> CREATE TABLE CLIENT (
2 CLIENTID NUMBER PRIMARY KEY,
3 NAME VARCHAR2(10)
4 );
Table created.
SQL> CREATE TABLE PROJECT(
2 PROJECTID NUMBER PRIMARY KEY,
3 NAME VARCHAR2(10),
4 CLIENTID REFERENCES CLIENT(CLIENTID)
5 );
Table created.
SQL> insert into client values(1, 'Naveen');
1 row created.
SQL> insert into client values(2, 'Santosh');
1 row created.
SQL> insert into project values(1, 'Oracle', 1);
1 row created.
SQL> insert into project values(2, 'Java', 1);
1 row created.
SQL> insert into project values(3, 'SQL', 2);
1 row created.
SQL> commit;
Commit complete.
SQL> ed
Wrote file afiedt.buf
1 SELECT name
2 FROM (SELECT c.name, COUNT(p.clientid) p_count
3 FROM client c, project p
4 WHERE c.clientid = p.clientid
5 GROUP BY c.name) a,
6 (SELECT MAX(COUNT(clientid)) p_max
7 FROM project
8 GROUP BY clientid) b
9* WHERE a.p_count = b.p_max
SQL> I can run your query, then what's the problem?
SQL>
Regards
Naveen
-----Original Message-----
From: Santosh Varma [mailto:vsantosh_at_psi.soft.net]
Sent: Thursday, October 03, 2002 2:53 PM
To: Multiple recipients of list ORACLE-L
Subject: Sql query
cannot perform an aggregate function on an expression containing an
aggregate or subquery
is the error i am getting while i am executing the query.
SELECT name
FROM (SELECT c.name, COUNT(p.clientid) p_count
FROM client c, project p
WHERE c.clientid = p.clientid
GROUP BY c.name) a,
(SELECT MAX(COUNT(clientid)) p_max
FROM project
GROUP BY clientid) b
WHERE a.p_count = b.p_max
clientid and name are the columns in client table
and projectid and clientid are the columns in project table.
santosh
-----Original Message-----
Ignaszak
Sent: Monday, September 30, 2002 6:09 PM
To: Multiple recipients of list ORACLE-L
try it:
select
name
from
(select c.name, count(p.id) p_count from clients c, projects p
where c.id = p.cl_id
group by c.name) a,
(select max(count(id)) p_max from projects
group by cl_id) b
where a.p_count = b.p_max
Regards,
Leszek
At 03:23 2002-09-30 -0800, you wrote:
>Hello all,
>
> I have a query ->
>i have 2 tables -> client and project
>
>fields in project table -> clientid/projectid
>fields in client table -> clientid/name
>
>i want to get the maximum orders one client has got. i mean a project
>having the greatest clients
>how to write it in single query ??
>
>
>like
>project 1 client 1
>project 2 client 1
>project 3 client 2
>
>in the above case, the query should return client ( 1 ).
>
>Thanks and regards,
>Santosh
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--
Author: Leszek Ignaszak
INET: leszek.ignaszak_at_post.pl
Fat City Network Services -- 858-538-5051 http://www.fatcity.com
San Diego, California -- Mailing list and web hosting services
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Author: Santosh Varma
INET: vsantosh_at_psi.soft.net
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-- Please see the official ORACLE-L FAQ: http://www.orafaq.com -- Author: Igor Neyman INET: ineyman_at_perceptron.com Fat City Network Services -- 858-538-5051 http://www.fatcity.com San Diego, California -- Mailing list and web hosting services --------------------------------------------------------------------- To REMOVE yourself from this mailing list, send an E-Mail message to: ListGuru_at_fatcity.com (note EXACT spelling of 'ListGuru') and in the message BODY, include a line containing: UNSUB ORACLE-L (or the name of mailing list you want to be removed from). You may also send the HELP command for other information (like subscribing).Received on Fri Oct 04 2002 - 08:53:26 CDT
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