Re: Canonical DB
From: Gene Wirchenko <genew_at_ucantrade.com.NOTHERE>
Date: Fri, 23 Jun 2006 15:51:07 -0700
Message-ID: <ksro92ltturh343l6mh1839fnvif1thjee_at_4ax.com>
Date: Fri, 23 Jun 2006 15:51:07 -0700
Message-ID: <ksro92ltturh343l6mh1839fnvif1thjee_at_4ax.com>
On Fri, 23 Jun 2006 21:59:52 +0200, "Dmitry A. Kazakov" <mailbox_at_dmitry-kazakov.de> wrote:
>On Fri, 23 Jun 2006 15:37:54 +0200, mAsterdam wrote:
[snip]
>> These requirements establish K as a clean point type.
>> Aside: With the last condition deleted one can make a
>> circular K, having distance(k1, k2) <> distance(k2, k1).
>
>That won't be formally a distance, which is required to be symmetric.
Why must it be symmetric? A to B and B to A may be different distances if there are one-way routes involved. Or am I missing a point?
[snip]
Sincerely,
Gene Wirchenko Received on Sat Jun 24 2006 - 00:51:07 CEST