Re: Canonical DB
From: mAsterdam <mAsterdam_at_vrijdag.org>
Date: Sat, 24 Jun 2006 01:33:56 +0200
Message-ID: <449c79d1$0$31647$e4fe514c_at_news.xs4all.nl>
> point?
Date: Sat, 24 Jun 2006 01:33:56 +0200
Message-ID: <449c79d1$0$31647$e4fe514c_at_news.xs4all.nl>
Gene Wirchenko wrote:
> Dmitry A. Kazakov wrote:
>
>> mAsterdam wrote: >>>These requirements establish K as a clean point type. >>>Aside: With the last condition deleted one can make a >>>circular K, having distance(k1, k2) <> distance(k2, k1). >> >>That won't be formally a distance, which is required to be symmetric.> distances if there are one-way routes involved. Or am I missing a
>
> Why must it be symmetric? A to B and B to A may be different
> point?
*formally*
Apparently, it is one of those cases where the
math term and rest-of-the-world word have a
somewhat different interpretation.
Received on Sat Jun 24 2006 - 01:33:56 CEST