Re: Transitive Closure

• Post for FREE via your newsreader at post.usenet.com ****

"Alfredo Novoa" <alfredo_at_ncs.es> wrote in message news:e4330f45.0405180233.6de76ab9_at_posting.google.com...
> Paul <paul_at_test.com> wrote in message

news:<Hu2qc.4347$wI4.496108_at_wards.force9.net>...
>
> > What we're talking about here which I think is what Alfredo is
> > misunderstanding is commutativity of the "composition of operators"
> > operator.
>
> What do you call composition?

It is defined below. The * operation.

> To an n-ary operator?
>
> > So say we have unary operators f and g we can define the
> > operator "f*g" to be:
> >
> > (f*g)(x) = f(g(x)) for all x.
> >
> > Commutativity of this "*" operation just means that:
>
> So "*" is a binary operation.

It might be, but apparently you missed the point. The "binary" * operation is not commutative.

-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=

• Usenet.com - The #1 Usenet Newsgroup Service on The Planet! *** http://www.usenet.com Unlimited Download - 19 Seperate Servers - 90,000 groups - Uncensored -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=