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RE: Oracle password dictionary

From: Reidy, Ron <Ron.Reidy_at_arraybiopharma.com>
Date: Wed, 15 Jun 2005 10:37:36 -0600
Message-ID: <17CAB0BF27BCFC47B0E4554A0E2F962B439830@fiji.arraybp.com>


True enough. However, my job is to solve problems, not write apps. The = checks made by cracklib would need to be coded into a big PL/SQL routine = and then tested. I do not need to reinvent the wheel.



Ron Reidy
Lead DBA
Array BioPharma, Inc.

-----Original Message-----
From: oracle-l-bounce_at_freelists.org
[mailto:oracle-l-bounce_at_freelists.org]On Behalf Of Andre van Winssen Sent: Wednesday, June 15, 2005 10:32 AM
To: Reidy, Ron; thomas_arnezeder_at_non.agilent.com; oracle-l_at_freelists.org Subject: RE: Oracle password dictionary

Extproc is full of exploits itself.=20

If you cannot enforce enough password strength checking in plsql (password_verify_function) then why not use a stored procedure that = calls
some java class that sticks to all your business rules for this purpose?

Regards,
Andre v Winssen

-----Oorspronkelijk bericht-----
Van: oracle-l-bounce_at_freelists.org =
[mailto:oracle-l-bounce_at_freelists.org]
Namens Reidy, Ron
Verzonden: woensdag 15 juni 2005 17:53
Aan: thomas_arnezeder_at_non.agilent.com; oracle-l_at_freelists.org Onderwerp: RE: Oracle password dictionary

Yes. You can put a dictionary into the DB and then query against it.

We are using a extproc library callout to the cracklib library to =3D enforce password strength.



Ron Reidy
Lead DBA
Array BioPharma, Inc.

-----Original Message-----
From: oracle-l-bounce_at_freelists.org
[mailto:oracle-l-bounce_at_freelists.org]On Behalf Of thomas_arnezeder_at_non.agilent.com
Sent: Wednesday, June 15, 2005 9:48 AM
To: oracle-l_at_freelists.org
Subject: Oracle password dictionary

Got a question about password strength. It's possible to enforce the =3D complexity of a password in the password_verify_function. But is there a =
=3D

way to check an oracle pw against a dictionary at the time the pw gets =
=3D

changed (and perhaps reject the new pw)? On UX you have the ckpw tool =
=3D

where you can check against a pw dictionary.
=3D20

Thanks,
Thomas

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Received on Wed Jun 15 2005 - 13:11:50 CDT

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