Re: U_SUMMARIZE: how aggregate is calculated?

On Wed, 1 Dec 2004 15:19:43 -0800, "Mikito Harakiri" <mikharakiri_at_iahu.com> wrote:

>Suppose we have one column relation which is essentially a set of intervals:
>
>{[1,2], [3,5], [4,7]}
>
>and I want to project away the interval column and calculate aggregated
>value of SUM(1). What the result there would be? 3? 2? 7?

It depends on what a sum of intervals is for you.

For me it would be:

{1,2} U {3,4,5} U {4,5,6,7} = {1,2,3,4,5,6,7} = [1,7]

Regards
  Alfredo Received on Thu Dec 02 2004 - 01:59:26 CET