Re: Median with standard SQL

Your professor at the University of Illinois probably wants you to really think about this one and try lots of different things. Finding a ready-made answer in a newsgroup is not the best way to go in the long term. It is much better to try to figure it out on your own, so here is a hint:

The answer is constrained in the problem.

"Jess Likens" <likens_at_students.uiuc.edu> wrote in message news:wPT27.633$oz3.8465_at_vixen.cso.uiuc.edu...
> Well, I don't think that works for both even and odd numbers of rows. And
 I
> don't think it works if there are multiple rows with identical values.
 But
> thanks.
>
> -Jess
>
> "Aakash Bordia" <a_bordia_at_hotmail.com> wrote in message
> news:9ida78$vi6$1_at_stlnews.stl.ibm.com...
> > Hint....
> > select column from table O where (select count(*) from table where
> > column<O.column)=(select count(*)/2 from table)
> > Thanks
> > Aakash
> >
> > "Jess Likens" <likens_at_students.uiuc.edu> wrote in message
> > news:yqm27.364$oz3.4759_at_vixen.cso.uiuc.edu...
> > > Does anyone have a method to get the median of a relation using only
 the
> > > following SQL commands: SELECT, DISTINCT, WHERE, FROM, LIKE, EXISTS,
 IN,
> > > UNION, INTERSECT, EXCEPT/MINUS, ANY, ALL, COUNT, SUM, AVG, MAX, MIN,
 GROUP
> > > BY, HAVING, ORDER BY, JOIN? I can't seem to come up with anything.
 The
> > > median of n elements occurs at (n+1)/2 for an odd number of elements
 and
 it
> > > is the average of n/2 and n/2 and (n+1)/2. Any help would be much
> > > appreciated.
> > >
> > > -Jess
> > >
> > >
> >
> >
>
>
Received on Wed Jul 11 2001 - 16:04:20 CEST