Re: i want to print in single line pl/sql block

"Michel Cadot" <micadot{at}altern{dot}org> schreef in bericht news:46d45275$0$407$426a34cc_at_news.free.fr...
>
> "saiba" <saibhasker_at_gmail.com> a écrit dans le message de news:
> 1188296336.903895.292130_at_i38g2000prf.googlegroups.com...
> | how can i get output like this
> |
> | 1 = 1
> | 1+2 = 3
> | 1+2+3 = 6
> | ........
> | 1+2+3+4+5+6+7+8+9+10 = 55;
> | i have to print same order.
> |
> | i don't got it but i wrote something see and modify and send reply
> | ---
> | declare
> | v number := 0;
> | v1 number;
> | begin
> | for i in 1..10 loop
> | for j in 1..i loop
> | v:= v+j;
> | dbms_output.put_line(j);
> | if j<>i then
> | dbms_output.put_line(' + ');
> | end if;
> | end loop;
> | dbms_output.put_line(' = '||v);
> | v:=0;
> | end loop;
> | end;
> | /
> |
>
> Just for fun:
>
> SQL> col operation format a30 justify right
> SQL> col "SUM" format a5
> SQL> with data as ( select level lvl from dual connect by level <= 10 )
> 2 select lpad(substr(sys_connect_by_path(level,'+'),2)||' =',30)
> operation,
> 3 ( select to_char(sum(lvl))
> 4 from data b
> 5 connect by prior lvl = lvl+1
> 6 start with b.lvl = a.lvl ) "SUM"
> 7 from data a
> 8 connect by prior lvl = lvl-1
> 9 start with lvl = 1
> 10 order by lvl
> 11 /
> OPERATION SUM
> ------------------------------ -----
> 1 = 1
> 1+2 = 3
> 1+2+3 = 6
> 1+2+3+4 = 10
> 1+2+3+4+5 = 15
> 1+2+3+4+5+6 = 21
> 1+2+3+4+5+6+7 = 28
> 1+2+3+4+5+6+7+8 = 36
> 1+2+3+4+5+6+7+8+9 = 45
> 1+2+3+4+5+6+7+8+9+10 = 55
>
> 10 rows selected.
>
> Regards
> Michel Cadot
>
>

Michel,

A beauty (as always)

Shakespeare Received on Wed Aug 29 2007 - 14:00:47 CDT