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Home -> Community -> Usenet -> c.d.o.misc -> Re: select part of a string only
On Feb 15, 11:14 am, "Thiko!" <biwo..._at_hotmail.com> wrote:
> On Feb 15, 11:01 am, "Carlos" <miotromailcar..._at_netscape.net> wrote:
>
>
>
> > On 15 feb, 11:50, "Thiko!" <biwo..._at_hotmail.com> wrote:
>
> > > hi i have this text in v$parameter columns name and value:
>
> > > name: log_archive_dest_1
>
> > > value: LOCATION=/oraarch/oradata/flash_recovery_area/CPSLIVE/
> > > archivelog
>
> > > VALID_FOR=(ALL_LOGFILES,ALL_ROLES)
>
> > > DB_UNIQUE_NAME=CPSLIVE1p
>
> > > i do a select to return part of the LOCATION:
>
> > > select replace(nvl(value,'NULL'),'LOCATION=') from v$parameter where
> > > name = 'log_archive_dest_1';
>
> > > this returns:
>
> > > /oraarch/oradata/flash_recovery_area/CPSLIVE/archivelog
> > > VALID_FOR=(ALL_LOGFILES,ALL_ROLES)
> > > DB_UNIQUE_NAME=CPSLIVE1p
>
> > > Anybody know how i can truncate in my select statement to retrun me
> > > only '/oraarch/oradata/flash_recovery_area/CPSLIVE/archivelog' and not
> > > anything after this. i do not wish to include the VALID_FOR etc after
> > > it.
>
> > > many thanks.
>
> > > Thiko!
>
> > Use instr() and substr() together.
>
> > HTH.
>
> > Cheers.
>
> > Carlos.
>
> oh blimey, can u not write it for me!? ;)
>
> Thiko!
cant use instr() or substr() unfortunately as it wont be generic on servers with different directory locations. Received on Thu Feb 15 2007 - 07:38:42 CST
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