Re: data guard rac to single instance

From: Seth Miller <sethmiller.sm_at_gmail.com>
Date: Fri, 24 May 2019 10:30:53 -0500
Message-ID: <CAEueRAXrJW-CHN-yve-Rs77r12zhdEH3G__FSRyhGDzQxTWDiA_at_mail.gmail.com>



To be clear, you need a static entry in any case for the setup because the standby is in a mount state and won't register with the listener. The question is whether you need one after the standby has been created.

On Fri, May 24, 2019 at 10:19 AM Andrew Kerber <andrew.kerber_at_gmail.com> wrote:

> This is where it gets interesting. All the documentation I have found on
> MOS still says that you need the static listener entry in the
> listener.ora.
>
> On Thu, May 23, 2019 at 5:59 PM Seth Miller <sethmiller.sm_at_gmail.com>
> wrote:
>
>> It depends on whether you have grid infrastructure installed on the
>> single instance server or not. If you do and your instance is registered,
>> no static entry should be required. This is not new in 12c.
>>
>>
>>
>>
>> On Thu, May 23, 2019 at 5:24 PM Andrew Kerber <andrew.kerber_at_gmail.com>
>> wrote:
>>
>>> So, I have been doing some rac to single instance data guard setups, and
>>> I have found a couple of blogs which said that when using RAC 12c and
>>> above, a static listener entry is not required for the RAC side of data
>>> guard. I have found a metalink note that says the static listener entry is
>>> still required. An sr says the static listener entry is still needed, but
>>> it only cites the metalink note, so I give that only about a 50% chance of
>>> being correct. Has anyone hear tried this? I have always set up the static
>>> listener entry, and I expect it doesnt hurt. But is it required?
>>>
>>> --
>>> Andrew W. Kerber
>>>
>>> 'If at first you dont succeed, dont take up skydiving.'
>>>
>>
>
> --
> Andrew W. Kerber
>
> 'If at first you dont succeed, dont take up skydiving.'
>

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Received on Fri May 24 2019 - 17:30:53 CEST

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