Re: Very simple question to relational theorists.

From: Evgeniy Grigoriev <grigoriev.e_at_gmail.com>
Date: Tue, 11 Sep 2012 03:41:21 -0700 (PDT)
Message-ID: <38666459-d179-4e5b-9d69-02ad5c6a1c56_at_googlegroups.com>


Thank you Philip.

Once again to be clear.

"So if the wff R(A,B,...) denotes the predicate for R then the wff for R RENAME A TO N is R(N,B,...). If the wff S(X,Y,...,A,...) denotes the predicate for S then the wff for (R JOIN S) RENAME A TO N is R(N,B,...) AND S(X,Y,...,N,...). "

If a system calculates (X,Y,...,N,...) automatically (according to some predefined mnemonic rules) as (R JOIN S) RENAME A TO N is R(N,B,...), the system is not relational.

(Yes/No)?

But if a system allow the S relational to be calculated as the same as (R JOIN S) RENAME A TO N is R(N,B,...) by hand - the system is relational.

(Yes/No)?
Received on Tue Sep 11 2012 - 12:41:21 CEST

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