Re: Towards a definition of atomic

From: Marshall <marshall.spight_at_gmail.com>
Date: Fri, 1 Feb 2008 10:55:36 -0800 (PST)
Message-ID: <e3b9470d-30b3-47b7-bc4f-1e4bfba99590_at_i12g2000prf.googlegroups.com>


On Feb 1, 5:30 am, David BL <davi..._at_iinet.net.au> wrote:
> AFAIK the conventional wisdom is that no absolute definition of atomic
> exists for domain types. Throwing caution to the wind, in this post I
> wish to conjecture a definition of atomic that, perhaps with some more
> effort at its formalisation, can provide some absolute meaning for a
> given attribute within a given RDB schema.
>
> The examples are a little contrived, but are only meant to be
> illustrative.
>
> Example 1:
> "Einstein discovered the formula E = mc^2"
> "Newton discovered the formula F = ma"
>
> Example 2:
> "Bill is a parent of { Mary, John }"
> "Mary is a parent of { Don, Alex, Sue }"
>
> In example 1, in Prolog we can define a predicate 'discovered' to
> represent the two facts as follows
>
> discovered(einstein, eq(var("E"), prod(var("m"),
> pow(var("c"),num(2))))).
> discovered(newton, eq(var("F),prod(var("m"),var("a")))).
>
> In previous threads I have discussed how it is not possible to
> decompose the information in nested expressions into a set of
> propositions about the nodes without the introduction of node
> identifiers.
>
> By contrast, in example 2 it is straightforward to map the two facts
> into five (by decomposing the sets of children) as follows
>
> parent(bill,mary).
> parent(bill,john).
> parent(mary,don).
> parent(mary,alex).
> parent(mary,sue).

I think there is a hidden assumption here at work which is affecting your results. We know that people are all distinct; by convention you are using first name as a proxy for a person, and treating the first name as unique; this allows you to make sets of propositions without concern for losing information in the process.

In contrast, the nodes in an expression tree are *not* distinct and hence cannot be uniquely determined simply by their intrinsic value. (Which node am I referring to when I specify node "c" in the expression "E = m * c * c"?)

If we did not consider first name to be unique, we would have to introduce PersonId in your example 2 for it to work. Likewise, if we restrict ourselves to expression trees in which each number and each variable may appear only once, we would not need node ids in your example 1.

Here is a very interesting and subtle point: node ids (and ids in every other such situation) are not what they might appear to be at first blush. They are not an artifice of set theory or relation theory. Rather, they are precisely and exactly the *identity information* of *structures.*

Consider these two strings:

  1*2+3
  3*2+1

Are they identical? Certainly not! The first evaluates to 5 and the second evaluates to 7. And yet they have exactly the same set of operands, the same set of operators. The characters in the two strings are identical, and even have the same frequency.

But the structure is different.

I say "structure" and not "order" because we could as well consider the strings as expression trees instead, and leave order out entirely. (Especially when considering expression trees of commutative operators.)

If we do think of them as strings, then they are indeed structures, specifically ordered structures or sequences. In relational terms, we might write:

  { (4, +), (2, *), (5, 3), (1, 1), (3, 2) }

(Here the order of appearance of the parenthesized pairs is of course immaterial.)

So what are those things on the left of each pair? They are the structure of the expression in question! Are they "meaningless identifiers?" Certainly not! They are essential, and to remove them is to lose meaning. (Likewise, if we reorder the symbols in the original string we lose meaning.)

Now, in this case, the value of the identifiers of the symbols are used by the expression evaluator/parser, but this is just a distraction. Consider the evaluator for an expression tree expressed as a relation, which does not consider the values of the identifiers, and the fact that there is an isomorphism between them.

> Secondly (and this is where the examples are relevant), a valid
> decomposition must coincide with a defined bijection that maps a DB
> state in the original schema to a DB state in the new schema. This
> is where those node identifiers in the first example come to play,
> because they seem to be at odds with defining such a bijection.
> Putting it more simply, it seems that the node identifiers aren't
> functionally dependent on the original DB state. It is for this
> reason that one may claim that such a decomposition is unreasonable -
> in the sense of not achieving information equivalence as a set of
> propositions.
>
> Unfortunately, it seems that one could be tricky and come up with a
> bijection that makes the node identifiers functionally dependent on
> the underlying DB state; by defining some unique ordering on the
> identifiers (one could then use integers according to ordinal
> position). I say this is unfortunate because it upsets the proposal
> for a simple meaning of atomic. However, I wonder whether things can
> be salvaged at the expense of a complicated definition of atomic, by
> introducing a constraint on the bijection that it not be pathological,
> in the sense that addition of information shouldn't be able to cause
> widespread reassignment of identifiers. The very fact that this can
> happen points to their arbitrary or meaningless nature, and more
> specifically to the fact that they identify a sub-value rather than an
> entity in the UoD.
>
> Continuing with example 2, note that no further decomposition allowing
> information equivalence is possible. For example, a person's name is
> represented as a string domain type, and this is atomic because any
> attempt at decomposing the string into its individual characters
> forces the introduction of additional identifiers.

The concept we are running into here is the same as "alpha equivalence"
from lambda calculus.

Consider these two programs:

Program 1:
  let x=5;
  let y=3;
  x+y;

Program 2:
  let a=5;
  let b=3;
  a+b;

Are these programs identical? It depends on what we mean by "identical." Certainly they calculate the same value, but certainly that's not enough to consider them identical.

If we consider the two programs as strings of symbols, then obviously they are different. However clearly they are very closely related, and we can formalize this perception, and this formalization is called alpha equivalence. Roughly, the two programs are alpha equivalent because they have identical structure if we ignore the specific choices of variable names. From this perspective, there is no significance to the specific choice of "x" or "a" or whatever as variable names, but that doesn't mean the names are meaningless, because the distinct names encode identity within the structure they are embedded in.

Marshall Received on Fri Feb 01 2008 - 19:55:36 CET

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