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Home -> Community -> Usenet -> comp.databases.theory -> Re: completeness of the relational lattice
Hello Marshall and Vadim,
The axioms for equality axioms looked a bit ugly, so I wondered if that could be improved. I think we can if we introduce in analogy to [H] the operation <H> which denotes the relation with header H that contains all tuples of the form (x,x,..,x).
The syntax:
E ::= R | E * E | E + E | {()} | [H] | <H>
If we adapt the equations we get:
Standard equalities:
(1) r * r = r
(2) r * s = s * r
(3) r * (s * t) = (r * s) * t
(4) r + r = r
(5) r + s = s + r
(6) r + (s + t) = (r + s) + t
(7) r * {()} = r
(13) {()} = {()} + []
Special distribution equalities:
(8) r * (s + t) = (r * s) + (r * t)
if A(r) * A(s) <= A(t) or A(r) * A(t) <= A(s)
(9) r + (s * t) = (r + s) * (r + t)
if A(s) * A(t) <= A(r)
Absorption:
(20) r + (r * s) = r
(21) r * (r + s) = r
Empty relations:
(10) R = R + [H]
if H is the header of R
(11) [H] * [S] = [H + S]
(12) [H] + [S] = [H * S]
(22) R * [] = [H]
if H is the header of R
Equalities
(27) <H> * <S> = <H + S>
(28) R * <x> = R
if x in header H (NOTE x is a single attribute) (30) <> = {()}
Miscellaneous
(26) <H> + [S] = <H * S>
(29) [H] * <S> = [H + S]
(31) ((r * <S>) + [H]) * <S> = ((r * <S>) + [H'])
if S * H nonempty and H + S = H'
Looks better, no? :-)
Btw., important related literature: http://citeseer.ist.psu.edu/379191.html Vadim will like it, lots of lattices and cylindrical algebras. ;-)
Cheers,
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