Re: A new proof of the superiority of set oriented approaches: numerical/time serie linear interpolation
From: Bob Badour <bbadour_at_pei.sympatico.ca>
Date: Thu, 03 May 2007 16:24:56 -0300
Message-ID: <463a36d8$0$4048$9a566e8b_at_news.aliant.net>
>
> 1) What about my question above?
>
> 2) How about f(x)=sqrt(x)? For x>0, it has two answers. Try
> interpolating on that.
Date: Thu, 03 May 2007 16:24:56 -0300
Message-ID: <463a36d8$0$4048$9a566e8b_at_news.aliant.net>
Gene Wirchenko wrote:
> Bob Badour <bbadour_at_pei.sympatico.ca> wrote:
>
>
>>Gene Wirchenko wrote: >> >> >>>Bob Badour <bbadour_at_pei.sympatico.ca> wrote: >>> >>> >>> >>>>Gene Wirchenko wrote: >>>> >>>> >>>> >>>>>Bob Badour <bbadour_at_pei.sympatico.ca> wrote: >>>>> >>>>>[snip] >>> >>> >>>>>>Interpolation has a number of other traps. Suppose one evaluates: >>>>>>f(x) = (x-1)/(x-1) at x=0 and x=2. One will reach a vastly wrong >>>>>>conclusion if one even tries to interpolate f(1). >>>>> >>>>> What about if we limit it to functions? Your f is not a>
>
> ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
>>>>>function, because 1 is not in the domain. (I am assuming a general >>>>>(for lack of a better word) domain, such as N, Z, Q, or R.) >>>> >>>>If 1 were not in the domain, one would have no desire to interpolate to >>>>it in the first place. That sounds like ignoring the problem by defining >>>>it out of existence. >>> >>> If 1 is in the domain, then f(x) does not have a defined value >>>for 1, and is, thus, not a function. >> >>I don't recall claiming that f(x) was a function. I recall claiming it >>was a trap for interpolation.
>
> 1) What about my question above?
>
> 2) How about f(x)=sqrt(x)? For x>0, it has two answers. Try
> interpolating on that.
Ohhhh, I see! Nooow, I get it. D'Oh! Um, is the unit impulse function a function? What about the unit step function? Received on Thu May 03 2007 - 21:24:56 CEST