Re: abnormal forms
From: paul c <toledobythesea_at_oohay.ac>
Date: Thu, 20 Apr 2006 21:43:12 GMT
Message-ID: <QfT1g.51142$7a.36958_at_pd7tw1no>
>
>
> I assume by relation you mean relation variable.
>
>
> That would depend on the definition of the equality operator. Because
> the two relations have different types, the equality operator can either
> return false or cause a compile-time error.
> ...
>
>
> I disagree that #3 is a canonical form of either #1 or #2. Both #1 and
> #2 allow {{},1} but #3 does not.
> ...
Date: Thu, 20 Apr 2006 21:43:12 GMT
Message-ID: <QfT1g.51142$7a.36958_at_pd7tw1no>
Bob Badour wrote:
> paul c wrote:
>
>> Bob Badour wrote: >> >>> ... >> >> If you have relation
>
>
> I assume by relation you mean relation variable.
> ...
>
> If you mean 'comparable' in the sense of the relational equality
> operator that compares two relations for equality, then the answer is
> yes. The result of the comparison is false.
>
>
>> and is it relationally comparable to >> >> 3. SP{S,P} with value >> >> S P >> = - (where the '=' underscore means S is a 'key') >> 1 1 >> 2 1 >> >> ?
>
>
> That would depend on the definition of the equality operator. Because
> the two relations have different types, the equality operator can either
> return false or cause a compile-time error.
> ...
> ...
>> For sure, #3 is in a kind of canonical form as far as Codd was concerned.
>
>
> I disagree that #3 is a canonical form of either #1 or #2. Both #1 and
> #2 allow {{},1} but #3 does not.
> ...
p Received on Thu Apr 20 2006 - 23:43:12 CEST