Re: circular relationships ok?

From: JOG <jog_at_cs.nott.ac.uk>
Date: 4 Mar 2006 06:13:08 -0800
Message-ID: <1141481588.320097.191050@i39g2000cwa.googlegroups.com>

Brian Selzer wrote:
[snip]
> Then the following statements are true: A has value a. B has
> value b. C has value c. If {A, B} is a candidate key, then the statement "A
> has value a, and B has value b." implies the statement "C has value c."
> because by definition, the value of a candidate key determines all other
> values in a tuple.

or rather from his example, the proposition would be: A(a) ^ B(b) -> C(c) Received on Sat Mar 04 2006 - 08:13:08 CST