Re: What to call this operator?

In article <1120336537.052835.142450_at_o13g2000cwo.googlegroups.com>, mikharakiri_nospaum_at_yahoo.com says...
> Why? Consider functions of multiple variables. Function f(x)=sin(x) is
> equivalent to function f(x,y)=sin(x)*1(y), where 1(y) is constant
> function evaluating to 1.

Well, yes. What I meant to question was the sense in doing so (i.e. expressing a function in terms of irrelevant arguments). I would also question the definition of this equivalence since one function has two arguments and the other one. But never mind.

-- 
Jon