Re: bag intersection definition

From: Jan Hidders <jan.hidders_at_pandora.be>
Date: Tue, 09 Sep 2003 21:03:51 GMT
Message-ID: <Xer7b.11203$N37.412786_at_phobos.telenet-ops.be>


Mikito Harakiri wrote:

> The "standard" definition when
>
> {1,1,1} intersect {1,1} = {1,1}
>
> is just plain naive. Given that
>
> intersection = projection * equality selection * cross product
>
> (operator multiplication notation is right-associate)
>
> the definition should be:
>
> {1,1,1} intersect {1,1} = {1,1,1,1,1,1}

Yeah, but then you lose the equation that X intersect X = X. Anyway, this is largely esthetics.

  • Jan Hidders
Received on Tue Sep 09 2003 - 23:03:51 CEST

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