Re: Plural or singular table names
Date: Wed, 3 Sep 2003 15:09:08 -0400
Message-ID: <M9s5b.436$iP3.44134429_at_mantis.golden.net>
"Paul Vernon" <paul.vernon_at_ukk.ibmm.comm> wrote in message
news:bj59dh$13i2$1_at_gazette.almaden.ibm.com...
> "Bob Badour" <bbadour_at_golden.net> wrote in message
> news:Lwn5b.422$0G3.43916381_at_mantis.golden.net...
> [snip]
> > > > Consider the following relation:
> > >
> > > Relation variable or relation value?
> >
> > It doesn't matter. It is a relation with known constraints.
>
> Whether something is a value or a variable doesn't matter?
>
> > Values do have constraints; they have types.
>
> Nope, a type is part of the value.
I agree. The type constraint is part of the value. Thus A and B might both be unary relations with a single integer attribute C. A and B might both have a single tuple with the integer value 1 in C. If the candidate key of A is {} while the candidate key of B is { C }, then the type of A and the type of B are different. Likewise comparing two relations with different constraints Z = A + B and Z = A ^ B. The constraints are part of the type specification and affect the resulting values of operations on the values.
> > The relation F with a binary
> > key {X,Y} is different from a similar relation with a nullary key {}. A
> > relation value has a predicate and a body.
>
> Nope, a relation value has a heading and a body. The heading defines the
type of the
> value and is part of that value.
I prefer to say that a relation has a predicate and that the heading is a required part of the predicate. The predicate defines the type of the value and is part of that value.
> You do not take a relation body and add some type constraints. A relation
body cannot
> stand alone without it's header.
A relation body cannot stand alone without its predicate and the predicate requires a heading.
> A relation value has no information about constraints.
I disagree. Every relation has at least one candidate key, and the candidate keys can affect the result values of operations.
> It might satisfy certain
> constraints, but it does not 'contain' any constraints.
Again, I disagree. The constraints form the type specification.
> It might satisfy A -> B, but
> A -> B is not part of it's value - it would be redundant if it was because
we could
> derive the fact that A -> B from the actual value of the relation.
> A value is just a value. It is 'constrained' to be exactly the value that
it is. OK,
> so maybe that is one constraint.
A value has a type that affects its value. Received on Wed Sep 03 2003 - 21:09:08 CEST