SQL Troubles
Date: 17 Aug 94 15:11:48 GMT
Message-ID: <2722_at_intermec.UUCP>
> Laura _at_ljw_at_evolving.com on 17 Aug 1994 (titled: SQL Troubles) writes:
> I have a select statement that almost does what I want, but not quite....
> select count(column1)/(to_char(column2, 'HH24') - to_char(column3, 'HH24'))
> from my_table;
> column1, column2, and column3 are all columns of the type date and they
> get put into the database using the format 'YYYYMMDDHH24MISS'.
> The problem is, if column2='19940816020000' and column3='19940816043000'
> then effectively I am taking the difference between 4:30 and 2:00 but because
> of my 'HH24's, the difference is only 2 hours instead of 2.5. If I use
> formats of 'HH24MI' then the difference will return 230 and I will end up
> with some_number/230 when I really want some_number/2.5 hours.
> I have tried putting in a to_char to convert the difference into HH24MI
> but get the error ORA-01481: invalid number format model
> Any ideas?
> laura
I created a table my_table, and inserted some dates,
COL1 COL2 -------------------- -------------------- 01-JAN-1994 00:00:00 31-DEC-1994 23:59:59 01-FEB-1994 00:00:00 03-FEB-1994 06:30:00 16-AUG-1994 02:00:00 16-AUG-1994 04:30:00
Using Oracle date arithmetic which return days and multiplying by 24 hours,
SQL> l
1 select to_char( col1, 'DD-MON-YYY HH24:MI:SS' ) col1,
2 to_char( col2, 'DD-MON-YYY HH24:MI:SS' ) col2, 3 24*(col2 - col1)
4* from my_table
SQL> /
COL1 COL2 24*(COL2-COL1) -------------------- -------------------- -------------- 01-JAN-994 00:00:00 31-DEC-994 23:59:59 8759.99972 01-FEB-994 00:00:00 03-FEB-994 06:30:00 54.5 16-AUG-994 02:00:00 16-AUG-994 04:30:00 2.5
Hope this answers your question.
Adrian Wilson
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