Re: Cartesian join

From: <johnbhurley_at_sbcglobal.net>
Date: Mon, 2 Mar 2009 11:42:20 -0800 (PST)
Message-ID: <ef691aea-6627-4fa8-a90d-c9faae8d6523_at_x29g2000prf.googlegroups.com>

On Mar 2, 2:39 pm, Jorge Reyes <jorg_re..._at_hotmail.com> wrote:
> Hi everyone,
>
> I Hope can explain well my issue, i have 2 tables, 1 of them has a
> column which contains a phone number and other column which means the
> name of a client, the other table has 2 columns which means a range of
> phone numbers (init range and end range) so i want to get the amount
> of telephone numbers that do not fit in the range, something like
> this:
>
>          Table A
> Client       PhoneNumber
> Nextcom  222222222222
> Nextcom  444444444444
> Nextcom  111111111111
>
>          Table B
> InitRange       EndRange
> 2222222222   3333333333
> 5555555555   6666666666
>
> With this i will get an amount of 2 phone numbers are in Table A and
> are not in any range of Table B, thats what i want... BUT, today i
> have exactly the inverse, i make this:
>
> SELECT
>     COUNT(A.PHONE_NUMBER)
> FROM
>     om_db.CLIENTS A INNER JOIN om_db.RANGE B
> ON
>     A.PHONE_NUMBER between B.NIR_INICIAL AND B.NIR_FINAL
> WHERE
>     A.CLIENT = 'Nextcom0';
>
> With this i have an amount of 1 phone number, i probe with not between
> but its not the answer because the result is the product of the
> cartesian join, Table A has over 1,092 rows for that client (Nextcom0)
> and the catalog of Table B has 61,704 rows.
>
> Any suggestion please...:(

Is this a real world work based example or homework? Received on Mon Mar 02 2009 - 13:42:20 CST