Re: Cartesian join

From: Jorge Reyes <jorg_reyes_at_hotmail.com>
Date: Mon, 2 Mar 2009 13:44:42 -0800 (PST)
Message-ID: <476841af-8bc4-47b5-b23b-abe0ae89ec12_at_n33g2000vba.googlegroups.com>

On 2 mar, 13:42, johnbhur..._at_sbcglobal.net wrote:
> On Mar 2, 2:39 pm, Jorge Reyes <jorg_re..._at_hotmail.com> wrote:
>
>
>
> > Hi everyone,
>
> > I Hope can explain well my issue, i have 2 tables, 1 of them has a
> > column which contains a phone number and other column which means the
> > name of a client, the other table has 2 columns which means a range of
> > phone numbers (init range and end range) so i want to get the amount
> > of telephone numbers that do not fit in the range, something like
> > this:
>
> >          Table A
> > Client       PhoneNumber
> > Nextcom  222222222222
> > Nextcom  444444444444
> > Nextcom  111111111111
>
> >          Table B
> > InitRange       EndRange
> > 2222222222   3333333333
> > 5555555555   6666666666
>
> > With this i will get an amount of 2 phone numbers are in Table A and
> > are not in any range of Table B, thats what i want... BUT, today i
> > have exactly the inverse, i make this:
>
> > SELECT
> >     COUNT(A.PHONE_NUMBER)
> > FROM
> >     om_db.CLIENTS A INNER JOIN om_db.RANGE B
> > ON
> >     A.PHONE_NUMBER between B.NIR_INICIAL AND B.NIR_FINAL
> > WHERE
> >     A.CLIENT = 'Nextcom0';
>
> > With this i have an amount of 1 phone number, i probe with not between
> > but its not the answer because the result is the product of the
> > cartesian join, Table A has over 1,092 rows for that client (Nextcom0)
> > and the catalog of Table B has 61,704 rows.
>
> > Any suggestion please...:(
>
> Is this a real world work based example or homework?

Is a real world work, why? Received on Mon Mar 02 2009 - 15:44:42 CST