Re: is there a better way to do this?

On Feb 20, 6:44 am, Ben <benal..._at_yahoo.com> wrote:
> On Feb 19, 5:04 pm, "fitzjarr..._at_cox.net" <fitzjarr..._at_cox.net> wrote:
>
>
>
>
>
> > On Feb 19, 2:32 pm, Ben <benal..._at_yahoo.com> wrote:
>
> > > 10.2.0.2 EE
>
> > > Is there a more logical sql statement to get the same results than
> > > what I am running here?
>
> > > create table t (a number, b number);
>
> > > insert into t values (1, 1);
> > > insert into t values (1, 2);
> > > insert into t values (2, 3);
> > > insert into t values (3, 2);
> > > insert into t values (4, 4);
> > > insert into t values (4, 5);
> > > insert into t values (5, 1);
> > > insert into t values (6, 8);
> > > commit;
>
> > > select a.a, a.b
> > > from t a, (
> > > select b, count(distinct a)
> > > from t
> > > group by b
> > > having count(distinct a) > 1) b
> > > where a.b = b.b
>
> > >          A          B C                    D
> > > ---------- ---------- -------------------- --------------------
> > >          5          1 a                    a
> > >          1          1 a                    a
> > >          3          2 a                    a
> > >          1          2 a                    a
>
> > > What I am wanting are the values for A where B is the same.
>
> > What, exactly, does that last sentence mean?
>
> > David Fitzjarrell- Hide quoted text -
>
> > - Show quoted text -
>
> in the original post my table definition doesn't have a column C or D
> but the output shows them. I removed those columns from my post to try
> to avoid confusion and forgot to remove them from the output of the
> query.- Hide quoted text -
>
> - Show quoted text -

You need to read the text which was referenced, and it wasn't your tacked-on follow-up. Apparently David Portas could decipher this and provide a reasonable alternative.

David Fitzjarrell Received on Wed Feb 20 2008 - 07:30:30 CST