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Re: SQL to retrieve most recent row meeting criteria

From: Burt Peltier <burttemp1REMOVETHIS_at_bellsouth.net>
Date: Thu, 22 Jul 2004 23:11:27 -0500
Message-ID: <zd0Mc.4292$NQ5.1899@bignews4.bellsouth.net>


All kinds of ways to do everything.... not saying this is the best, but here is another option ...

select * from
(select zip from journal where email='xxx_at_yyy.com' order by id desc) where rownum < 2

-- 

"Art Krumsee" <akrumsee_at_columbus.rr.com> wrote in message
news:21MLc.227249$DG4.49690_at_fe2.columbus.rr.com...

> I've completed a port of my application to Oracle, SQL Server, MySQL and
> Teradata. That's been a learning effort of considerable proportions. But
I
> do have an Oracle question.
>
> I want to retrieve the most recent row from a table meeting a specific
> criteria. In the example below, I want the most recent zipcode of the
> individual with a specific email address. The table has an ID column
which
> increments automatically as rows are added. Right now I'm using:
>
> select zip from journal where id=(select max(id) from journal where
> email='xxx_at_yyy.com')
>
> This works but, even with optimized indexing, it requires two hits of the
> database to process. In SQL Server I was able to accomplish this in one
hit
> using their TOP syntax. Is there a more efficient way to accomplish this
in
> Oracle?
>
>
Received on Thu Jul 22 2004 - 23:11:27 CDT

Original text of this message

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