Re: please help with SQL query...

Thanks, I will try is right now...

Massimo :)

<tommychill_at_my-deja.com> wrote in message news:8o3pfu$6f8$1_at_nnrp1.deja.com...
> Unless someone comes up with a prettier solution, try this:
>
> SELECT MessageID(PK)
> FROM (SELECT OriginalMessageID, MAX(ExecDate) MAXDATE
> FROM table_name
> GROUP BY OriginalMessageID) a, table_name b
> WHERE MAXDATE = b.ExecDate
> AND a.OriginalMessageID = b.OriginalMessageID;
>
> Should work, even though its not so pretty...
>
>
> In article <JCcp5.15372$Z2.182255_at_nnrp1.uunet.ca>,
> "Massimo Di Marco" <massimo_at_sfcommerce.com> wrote:
> > I need some help to figure out how to do this query...
> >
> > Here is the data:
> >
> > OriginalMessageID MessageID(PK) ExecDate
> > 1 1234 10:20
> > 1 5FE2 10:55
> > 1 EA33 10:50
> > 2 4667 11:10
> > 2 98EA 10:13
> >
> > Now I need the MessageID for the latest record for each
 OriginalMessageID,
> > so the result would be:
> >
> > MessageID(PK)
> > 5FE2
> > 4667
> >
> > What would the SQL SELECT look like to get this result....
> >
> > Thanks
> > Massimo
> >
> >
>
>
> Sent via Deja.com http://www.deja.com/
> Before you buy.
Received on Thu Aug 24 2000 - 14:14:07 CDT