Re: DataGuard Bandwidth requirements

From: Pradeep Chetal <chetal_at_gmail.com>
Date: Wed, 13 May 2015 11:09:38 -0400
Message-ID: <CACQXv63fCAbZUdvnC-A4MeXgPgfKP4cWP=kTtcWAh-JPb2TEoA_at_mail.gmail.com>



bytes to bits

On Wed, May 13, 2015 at 10:47 AM, Sweetser, Joe <JSweetser_at_icat.com> wrote:

> A bit perplexing, these numbers are…..
>
>
>
> Doc ID 736755.1 has the formula and says it assumes a 30% overhead for
> TCP/IP, so I think .7 is 70% utilization. I also think the 1,000,000 is
> just to get the answer mb’s. But I can’t figure out where the 8 comes from
> in the formula.
>
>
>
> -joe
>
>
>
> *From:* oracle-l-bounce_at_freelists.org [mailto:
> oracle-l-bounce_at_freelists.org] *On Behalf Of *max scalf
> *Sent:* Wednesday, May 13, 2015 7:29 AM
> *To:* Oracle Mailing List
> *Subject:* DataGuard Bandwidth requirements
>
>
>
> Hello list,
>
>
>
> we are in process of deploying a Data guard and i am looking to get a
> bandwidth requirements. While googleing i came across the below formula
> multiple times..my question is what exactly do the below numbers represents
> 0.7, 8, 1000000 ?? i know we can get and redo rate bytes per sec from
> v$sysmetric_history but confused on the numbers...
>
>
>
> *Required bandwidth = ((Redo rate bytes per sec. / 0.7) * 8) / 1,000,000
> = bandwidth in Mbps *
>
>
>
>
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Received on Wed May 13 2015 - 17:09:38 CEST

Original text of this message