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From: paul c <toledobythesea@oohay.ac>
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Subject: Re: Foreign superkey support
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Date: Tue, 08 Aug 2006 18:28:55 GMT
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Marshall wrote:
> paul c wrote:
>> Perhaps all I'm saying is that the basic relational algebra doesn't need
>> a foreign key concept which I admit is a deviation from the specific
>> question.
> 
> I don't think of constraints as being part of the algebra per se.
>  ...

If they aren't, I think that would mean the algebra is incomplete (and 
every relation's value could only get 'larger', until it reached the 
product of its domains' values which could then never be 'constrained' 
to a smaller set).

p
