Re: Taking floor of date

How about this:

    SELECT * FROM TABLE
    WHERE ROUND(date_column, 'DAY') = ROUND(another_date, 'DAY');

• Greg Johnson

Roy Smith wrote:

> I've got a table with a DATE datatype column in it. I want to select all
> the rows which contain dates which are the same calendar day as another
> date I've got. What's the best way to do that?
>
> One way I can see to do that would be to take the integer part of my
> selection date, which would give me time 00:00:00 of that date, then add 1
> to it, giving me 00:00:00 of the next date, then doing:
>
> select * from table where date >= midnight_today and date < midnight_tomorrow
>
> but I don't see any way to do the "take the integer part" bit.
>
> The only way I can see to do this is to use the to_char function,
> converting just the year, month, and day-of-month, then use to_date to
> convert that back to a DATE datatype, but that's pretty gross.
>
> --
> Roy Smith <roy_at_popmail.med.nyu.edu>
> New York University School of Medicine
Received on Thu May 13 1999 - 09:46:11 CDT