Re: Problem with simple histogram query

Hello,

Thanks. We are thinking along the same lines, I just tried the same thing. Unfortunately, it did not help.

I think the general problem is that I need to make a right outer join between coeffdescription and the RESULT of the inner join between sample and scurve, not just scurve. I've reduced the query, and it works fine until I add the join between sample and scurve.

Any hints on how to ensure the right outer join relates to the result of the inner join? I guess I would need a subquery and use this in the right outer join?

Regards,

Knut

"Rene Nyffenegger" <rene.nyffenegger_at_gmx.ch> wrote in message news:bhdc19$vlfs9$1_at_ID-82536.news.uni-berlin.de...
>
> > Hello,
> >
> > Thank you very much for your reply, that works fine. (Still a problem,
> > though, see below.) Using the old Oracle syntax (we're developing on 9,
but
> > also testing on 8) also works:
> >
> > select count(sc.uniformity) as occurrences, cd.description
> > from sc2 sc, cd2 cd
> > where sc.uniformity(+) >= cd.minvalue
> > and sc.uniformity(+) < cd.maxvalue
> > group by cd.description;
> >
> > But I'm still having a problem when extending this simple example to our
> > "real" query, which involves two more tables with inner joins to the two
> > tables that have a right outer join.
> >
> > To illustrate, let me show some partial queries. The one below shows the
> > dataset we will be counting, having 2 records:
> >
> > select sc.sampleid, sc.uniformity
> > from scurve sc, sample s
> > where s.wellid in (101)
> > and sc.typeid = 1
> > and s.s_id = sc.sampleid
> > and s.depth >= 1100
> > and s.depth <= 1200;
> >
> > SAMPLEID UNIFORMITY
> > ---------- ----------
> > 181 2,639
> > 182 3,533
> >
> > Next, the categories to which they will be assigned, are:
> >
> > select (cd.minvalue || ' to ' || cd.maxvalue) as interval,
cd.description
> > from coeffdescription cd, coefftype ct
> > where ct.co_id = cd.coefftypeid
> > and ct.type = 'Uniformity'
> > order by cd.minvalue;
> >
> > INTERVAL DESCRIPTION
> > ---------------- ---
> > 0 to 3 Uniform sand
> > 3 to 5 Intermediate: 3<Uc<5
> > 5 to 999999 Non-uniform sand
> >
> > So, the resulting combined query should have counts 1 for the first and
> > second category, but 0 for the third:
> >
> > select count(sc.uniformity) as occurrences, (cd.minvalue || ' to ' ||
> > cd.maxvalue) as interval, cd.description
> > from scurve sc, coeffdescription cd, coefftype ct, sample s
> > where s.wellid in (101)
> > and sc.uniformity(+) >= cd.minvalue
> > and sc.uniformity(+) < cd.maxvalue
> > and sc.typeid = 1
> > and s.s_id = sc.sampleid
> > and ct.co_id = cd.coefftypeid
> > and ct.type = 'Uniformity'
> > and s.depth >= 1100
> > and s.depth <= 1200
> > group by cd.minvalue, cd.maxvalue, cd.description
> > order by cd.minvalue;
> >
> > OCCURRENCES INTERVAL DESCRIPTION
> > ----------- ---------- ---
> > 1 0 to 3 Uniform sand
> > 1 3 to 5 Intermediate: 3<Uc<5
> >
> > The problem is, there is no count for the third category (should have
been
> > count 0).
> >
> > I also tried the newer syntax for the outer join, but with the same
result
> > (sorry about the mixed old and new syntax):
> >
> > select count(sc.uniformity) as occurrences, (cd.minvalue || ' to ' ||
> > cd.maxvalue) as interval, cd.description
> > from scurve sc RIGHT OUTER JOIN coeffdescription cd ON
> > (sc.uniformity >= cd.minvalue
> > and sc.uniformity < cd.maxvalue), coefftype ct, sample s
> > where s.wellid in (101)
> > and s.s_id = sc.sampleid
> > and sc.typeid = 1
> > and ct.co_id = cd.coefftypeid
> > and ct.type = 'Uniformity'
> > and s.depth >= 1100
> > and s.depth <= 1200
> > group by cd.minvalue, cd.maxvalue, cd.description
> > order by cd.minvalue;
> >
> > From what I can see, the joins must be:
> >
> > - Inner join between sample and scurve
> > - Right outer join between scurve and coeffdescription
> > - Inner join between coeffdescription and coefftype
> >
> > Any hints on what is wrong would be appreciated! (Regarding syntax, it's
> > sufficient that the solution works on Oracle 9).
> >
> > Regards,
> >
> > Knut
> >
> >
> > -----
> >
> > "Isaac Blank" <izblank_at_yahoo.com> wrote in message
> > news:EB9_a.145$Mp1.20900925_at_newssvr21.news.prodigy.com...
> >> select count(sc.uniformity) as occurrences, cd.description
> >> from sc2 sc RIGHT OUTER JOIN cd2 cd
> >> ON sc.uniformity >= cd.minvalue
> >> and sc.uniformity < cd.maxvalue
> >> group by cd.description
> >>
> >>
> >> "Knut Hovda" <knut.hovda_at_pti.no> wrote in message
> >> news:7N6_a.1487$dbb.185756160_at_news.telia.no...
> >> > Hello,
> >> >
> >> > We have a problem with a query to create a histogram (counting
> > occurrences
> >> > in categories). Consider the following simplified example:
> >> >
> >> > create table cd2 (minvalue number(16), maxvalue number(16),
description
> >> > varchar(30));
> >> > create table sc2 (uniformity number(16));
> >> > insert into cd2 values (0,2,'small');
> >> > insert into cd2 values (2,4,'medium');
> >> > insert into cd2 values (4,6,'large');
> >> > insert into sc2 values (1);
> >> > insert into sc2 values (3);
> >> >
> >> > select count(*) as occurrences, cd.description
> >> > from sc2 sc, cd2 cd
> >> > where sc.uniformity >= cd.minvalue
> >> > and sc.uniformity < cd.maxvalue
> >> > group by cd.description;
> >> >
> >> > gives
> >> >
> >> > OCCURRENCES DESCRIPTION
> >> > ----------- --------------
> >> > 1 medium
> >> > 1 small
> >> >
> >> > But note that the 'large' category is not displaying, since no rows
in
> > sc2
> >> > fall in this category . We want the result to display (sorting order
is
> >> not
> >> > relevant):
> >> >
> >> > 0 large
> >> > 1 medium
> >> > 1 small
> >> >
> >> > How can we achieve this? (We first thought this was a simple matter
of
> > an
> >> > outer join missing, but somehow we seem to miss the trick here.)
> >> >
> >> > In advance, thanks for your help.
> >> >
> >> > Regards,
> >> >
> >> > Knut
> >> >
> >> >
> >>
>
>
> and sc.typeid(+) = 1
> ^^^
>
> Not testet as I was too lazy trying to understand your tables and the
> like.
>
> Still hope it helps
>
> Rene
>
> --
> Rene Nyffenegger
> www.adp-gmbh.ch
Received on Wed Aug 13 2003 - 08:07:42 CDT