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Home -> Community -> Usenet -> c.d.o.tools -> Re: Dates
I did something like this once when I needed to get years. Create a table with 31 rows, with the rows having the values from 1-31.
SQL> SELECT * FROM MON
2 /
MON_DAY
1
2
3
4
5
6
7
8
9
10
11
MON_DAY
12
13
14
15
16
17
18
19
20
21
22
MON_DAY
23
24
25
26
27
28
29
30
31
31 rows selected.
Then us a query like the one shown here:
SQL> SELECT mon_day, TO_CHAR(SYSDATE,'Mon') ||
2 '-' || LTRIM(TO_CHAR(mon_day)) 3 || '-' || TO_CHAR(SYSDATE,'YYYY')4 FROM mon
MON_DAY TO_CHAR(SYSDATE,'MON')||'-'||LTRIM(TO_CHAR(MON_DA
---------- -------------------------------------------------
1 May-1-2000
2 May-2-2000
3 May-3-2000
4 May-4-2000
5 May-5-2000
6 May-6-2000
7 May-7-2000
8 May-8-2000
9 May-9-2000
10 May-10-2000
11 May-11-2000
MON_DAY TO_CHAR(SYSDATE,'MON')||'-'||LTRIM(TO_CHAR(MON_DA
---------- -------------------------------------------------
12 May-12-2000
13 May-13-2000
14 May-14-2000
15 May-15-2000
16 May-16-2000
17 May-17-2000
18 May-18-2000
19 May-19-2000
20 May-20-2000
21 May-21-2000
22 May-22-2000
MON_DAY TO_CHAR(SYSDATE,'MON')||'-'||LTRIM(TO_CHAR(MON_DA
---------- -------------------------------------------------
23 May-23-2000
24 May-24-2000
25 May-25-2000
26 May-26-2000
27 May-27-2000
28 May-28-2000
29 May-29-2000
30 May-30-2000
31 May-31-2000
31 rows selected.
There may be some ways to avoid so many conversions. I'd have to think about that for awhile.
Hope this helps,
Jonathan
On Wed, 24 May 2000 15:01:42 -0500, Eleanor Sokol <eleanor_sokol_at_bmc.com> wrote:
>I'm trying to create a SQL statement which will give me all the days of
>a given month as individual rows. That is, the first row would be for
>01May00, the 2nd row would have 02May00, through 31May00.
Received on Thu May 25 2000 - 00:00:00 CDT
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