From oracle-l-bounce@freelists.org Thu Sep 9 14:34:55 2004 Return-Path: Received: from air189.startdedicated.com (root@localhost) by orafaq.com (8.11.6/8.11.6) with ESMTP id i89JYt913695 for ; Thu, 9 Sep 2004 14:34:55 -0500 X-ClientAddr: 206.53.239.180 Received: from turing.freelists.org (freelists-180.iquest.net [206.53.239.180]) by air189.startdedicated.com (8.11.6/8.11.6) with ESMTP id i89JYtI13690 for ; Thu, 9 Sep 2004 14:34:55 -0500 Received: from localhost (localhost [127.0.0.1]) by turing.freelists.org (Avenir Technologies Mail Multiplex) with ESMTP id C890E72CE71; Thu, 9 Sep 2004 14:36:30 -0500 (EST) Received: from turing.freelists.org ([127.0.0.1]) by localhost (turing [127.0.0.1]) (amavisd-new, port 10024) with ESMTP id 08334-65; Thu, 9 Sep 2004 14:36:30 -0500 (EST) Received: from turing (localhost [127.0.0.1]) by turing.freelists.org (Avenir Technologies Mail Multiplex) with ESMTP id 3881472D171; Thu, 9 Sep 2004 14:36:30 -0500 (EST) From: "Igor Neyman" To: , Subject: RE: writing "recursive SQL" Date: Thu, 9 Sep 2004 15:39:25 -0400 Message-ID: <003001c496a4$b6723f00$0704a8c0@development.perceptron.com> MIME-Version: 1.0 Content-type: text/plain; charset=US-ASCII Content-Transfer-Encoding: 8bit In-Reply-To: <20040909192716.29904.qmail@web53302.mail.yahoo.com> X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 X-archive-position: 9330 X-ecartis-version: Ecartis v1.0.0 Sender: oracle-l-bounce@freelists.org Errors-To: oracle-l-bounce@freelists.org X-original-sender: ineyman@perceptron.com Precedence: normal Reply-To: ineyman@perceptron.com X-list: oracle-l X-Virus-Scanned: by amavisd-new at freelists.org It's called hierachical query. Check "connect by ... prior ... start with..." in SQL manual. Igor Neyman, OCP DBA ineyman@perceptron.com -----Original Message----- From: oracle-l-bounce@freelists.org [mailto:oracle-l-bounce@freelists.org] On Behalf Of susan lam Sent: Thursday, September 09, 2004 2:27 PM To: oracle-l@freelists.org Subject: writing "recursive SQL" Hi, I would like to write a SQL to recursively extract data from a table. The algorithm is as follows: SQL> select * from mytable; A B ---------- ---------- 1 2 2 3 3 4 4 5 5 6 0 7 7 8 8 9 8 rows selected. If A=3, output the corresponding value of B (ie 4), then match B (ie 4) with A and output the next corresponding value of B (ie 5) and so on... Recursion stops when B != A A & B are unqiue and A= is a user input value The result I'm looking for is: if A=3, then the output is: 4 5 6 if A=7, then the output is: 8 9 Is there a way to accomplish that in SQL? thanks. susan __________________________________ Do you Yahoo!? Yahoo! Mail - You care about security. So do we. http://promotions.yahoo.com/new_mail -- To unsubscribe - mailto:oracle-l-request@freelists.org&subject=unsubscribe To search the archives - http://www.freelists.org/archives/oracle-l/ -- To unsubscribe - mailto:oracle-l-request@freelists.org&subject=unsubscribe To search the archives - http://www.freelists.org/archives/oracle-l/