Oracle-L: RE: Select count(name) from table group by name where count(name)

From: Fink, Dan <Dan.Fink_at_mdx.com>
Date: Thu, 29 Aug 2002 15:47:08 -0800
Message-ID: <F001.004C3699.20020829154708@fatcity.com>

Use HAVING count(name) = 1

Example from our good friend scott.emp

SQL> select job, count(job)
2 from emp
3 group by job;

JOB COUNT(JOB)
--------- ----------

ANALYST            2
CLERK              4
MANAGER            3
PRESIDENT          1
SALESMAN           4
                   0

6 rows selected.

SQL> i
  4 having count(job) = 1
  5
SQL> l
  1 select job, count(job)
  2 from emp
  3 group by job
  4* having count(job) = 1
SQL> / JOB COUNT(JOB)
--------- ----------
PRESIDENT 1 -----Original Message-----
Sent: Thursday, August 29, 2002 4:39 PM
To: Multiple recipients of list ORACLE-L 1

Hello guys,

I am baffled by this problem.

I need to fish out the person's name from a list but I only want the name of the person that occurs once in the list - minus those names that occurs more than once.

Now, I know about "distinct" and "unique", but this is not what I want. All I want is to be able to fish out the names of the people who have only one and exactly only one entry in the list. I do not want the names of those people who have more than one entry in the list.

Could one of you do me a huge favor give me some hints as to how to contruct the select statement for this.

Thanks.

ltiu

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Author: ltiu
INET: ltiu_at_alumni.sfu.ca

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Author: Fink, Dan
INET: Dan.Fink_at_mdx.com

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