Re: Sightly OT: Unix scripting

(all examples are using /usr/bin/ksh shell)

You could do it this way:

DATE=$(date '+%y%j')
DATE=$((${DATE} - 1))
[ ${#DATE} -eq 4 ] && DATE="0${DATE}"

But you have bigger problems my friend. What happens if the date is 02001 and you subtract 1. The result is 02000 which is invalid. Since you are in a script that is using the db anyway why not do something like this:

{
  sqlplus -s /nolog <<EOF
    connect /
    set pagesize 0
    select to_char(sysdate - 1, 'YYDDD') from dual;     exit;
  EOF
} | grep -iv connected | read DATE

Brian P. MacLean
Oracle DBA, OCP8i

                                                                                                              
                    "Ball, Terry"                                                                             
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                    03/21/02 12:08                                                                            
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Environment: Oracle 8.1.6.3 on Solaris 5.8

I am not a Unix Guru by any strech of the imagination, so I can use all the help I can get. I am trying to write a shell script to execute sqlldr of a file whose name includes yesterday's 2 digit year and julian day in the format: file_yyjjj.csv. I can get today's date fine by setting a variable to be DATE=`date '+%y%j'`

But when I try to get DATE -1 it strips the leading 0 (since it is currently
02). Does anyone have any suggestions as to how I can retain the leading 0 and still get yesterday's date?

TIA, Terry

Terry Ball, DBA
Birch Telecom
Work: 816-300-1335
FAX: 816-300-1801

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