RE: sequence of numbers

From: Jeffery Stevenson <jeff_at_mpv.com>
Date: Mon, 19 Nov 2001 06:42:59 -0800
Message-ID: <F001.003C86EE.20011119055021@fatcity.com>

Are the numbers actually in sequential order in the mt1 column? If so, you could probably do the following:

select m.row_num
from (select mt1, rownum row_num from mt) m where m.mt1 > m.row_num
and rownum = 1;

...but it will only work if the values are actually in order for mt1.

Jeffery Stevenson
Databeast Slayer
Medical Present Value, Inc.
Austin, TX

-----Original Message-----
Sent: Monday, November 19, 2001 5:40 AM
To: Multiple recipients of list ORACLE-L

Hello,

I've a table mt ( mt1 NUMBER(10) NOT NULL ) with unique index on the mt1
column.
There's a sequence of numbers 1,2,3,4,6,7,8,10,11 ... in the mt1

Now, I want to get the smallest number which is not in mt1 (excluding min(mt1)-x of course) into XY (in my example is it n. 5).

When I use SELECT MIN(mt1)-1 INTO XY FROM MT WHERE MT1 NOT IN (select mt1+1
from mt)
my perfromance goes pretty down :-))) (there's about 5 mil. of numbers).

Some idea how to get it without cursor?

Thanks (and sorry it's monday)
JP
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Author: Jeffery Stevenson
INET: jeff_at_mpv.com

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