Jan Hidders <hidders_at_gmail.com> wrote in
news:1187723867.532149.53830_at_57g2000hsv.googlegroups.com:
> On 21 aug, 17:19, "V.J. Kumar" <vjkm..._at_gmail.com> wrote:
>> Jan Hidders <hidd..._at_gmail.com> wrote
>> innews:1187699645.789970.23980_at_57g2000hsv.googlegroups.com:
>>
>>
>>
>> > On 21 aug, 01:13, "V.J. Kumar" <vjkm..._at_gmail.com> wrote:
>> >> Jan Hidders <hidd..._at_gmail.com> wrote
>> >> innews:1187645998.798282.58960_at_g4g2000hsf.googlegroups.com:
>>
>> >> > On 20 aug, 17:14, "V.J. Kumar" <vjkm..._at_gmail.com> wrote:
>> >> >> Jan Hidders <hidd..._at_gmail.com> wrote in
>> >> >> news:1187599195.269472.153110 @a39g2000hsc.googlegroups.com:
>>
>> >> >> > On 20 aug, 01:48, "V.J. Kumar" <vjkm..._at_gmail.com> wrote:
>> >> >> >> I wonder what the truth tables for 'AND' and 'OR' would look
>> >> >> >> like with the DEF operator. Could you show those tables ?
>>
>> >> >> > They would be the usual table you already gave:
>>
>> >> >> >> x y AND
>> >> >> >> -------
>> >> >> >> defined
>> >> >> >> 0 0 0
>> >> >> >> 1 0 0
>> >> >> >> 0 1 0
>> >> >> >> 1 1 1
>>
>> >> >> What is 'x AND y' equal to if x is '1' and y is not defined ?
>>
>> >> > The database would not allow you to write that. If y is nullable
>> >> > then it forces you to write "DEF y : x AND y".
>>
>> >> What is DEF y : x AND y equal to if x is '1' and y is not defined
>> >> ?
>>
>> > False. Because DEF y : f(y) means that (1) y is defined and (2)
>> > f(y) holds.
>>
>> So you convert undefined operands in your logical formulas to
>> 'false'.
>
> No. There is no conversion necessary. That's the whole point.
I do not understand. You have:
DEF y y DEF y:y
1 1 1 (1)
1 0 0 (2)
0 0 (3)
So 'DEF y:y' will give the same result when y is either undefined or
'false', rows (2) and (3). How is it not substituting 'false' for
undefined ?
>
> -- Jan Hidders
>
>
Received on Tue Aug 21 2007 - 15:20:03 CDT
