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Home -> Community -> Usenet -> comp.databases.theory -> Re: RA with MV attributes
David wrote:
> Aloha Kakuikanu wrote:
> > Never mind. Partial order is not enough. It has to be total order.
> >
> > Aloha Kakuikanu wrote:
> > > David wrote:
> > > > Here is a partial formalization of a relational algebra based on MV
> > > > attributes. The approach appears simple and intuitive. In particular
> > > > the join of two relations is rather elegant.
> > > > ...
> > >
> > > IMO, RA with MV attributes is quite easy to formalize. I suggest a
> > > nested relation as a formal definition for MV attribute. A critical
> > > step is noticing that there is a (partial) order "<" among all the
> > > relations. Formally:
> > >
> > > Q < R iff Q /\ R = R
> > >
> > > where "/\" is a symbol for relational join. (I don't quite like the
> > > "&&" symbol that Marshall uses:-)
> > >
> > > Next,
> > >
> > > Q = R iff Q < R and R < Q
> > >
> > > Now that we can compare relational valued attributes, we can define all
> > > the RA operations. Interestingly, set joins (and relational division)
> > > are easily expressed in this framework. For example, given
> > >
> > > A = { <x=1, y={<t=a>,<t=b>}> , <x=2, y={<t=b>,<t=c>} > }
> > >
> > > B = { <y={<t=a>} }
> > >
> > > Then, inequality join
> > >
> > > A /\_a.y<b.y B
> > >
> > > is the same as relational division between "flattened" A and B
> > > relations.
>
Can you please be more specific? Which kind of join do you have in mind? Here is case by case analysis:
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