Re: Proposal: 6NF

From: Cimode <cimode_at_hotmail.com>
Date: 21 Oct 2006 10:57:45 -0700
Message-ID: <1161453465.477273.179760_at_e3g2000cwe.googlegroups.com>


Brian Selzer wrote:

> Since it is clearly possible to divide and subtract some pairs of natural
> numbers such that the result is a natural number, what do you call those
> relationships?
Examples and behaviors do not make demonstrations. Idiot.

> Magic? Why is it said that N is not closed under
> subtraction and that Z is not closed under division if those binary
> operations, division and subtraction, are not conceptual relationships that
> transcend the definition of any single numeric domain? Or conversely, why
> is the operator "+" called addition in each of N, Z, Q, R and C? Is it true
> that if a number belongs to N it cannot also belong to R? Isn't the integer
> 5 equivalent to the rational number 5/1? Can you not add an integer to a
> rational number? How about a real number to a complex number? If not, then
> what does the "+" mean in the complex number, 5 + 3i? Is 5 + 0i + 0 + 3i
> meaningless?
These must be the dummest questions I have seen in this thread...

> The thing I consider moronic is supporting an argument by using a definition
> for a "value" that is clearly circular, that is, a value must be the output
> of a function. Is the input of that function, then, NOT a value? Are the
> elements of a set NOT values unless there is a function defined that ranges
> over that set?

A value is by definition the predetermined output of a specific function be it a relation or any function. If you find such definition *moronic* then you are finding math *moronic*

Not convinced, check

http://en.wikipedia.org/wiki/Value_%28mathematics%29

Besides, the fact of being by definition the output of some kind of transformation does not prevent it from being the input of another function.... DUHHHHHH!!

If value B is defined as F(A) = B nothing prevents it from being an input for another function, say V that produces C and inputing...In such case, V(B) = C and therefore V(F(A)) = C

There's nothing circular about that dumb ass, except in your confused mind.... Received on Sat Oct 21 2006 - 19:57:45 CEST

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