Gene Wirchenko wrote:
> Dmitry A. Kazakov wrote:
>
>> mAsterdam wrote:
>>>These requirements establish K as a clean point type.
>>>Aside: With the last condition deleted one can make a
>>>circular K, having distance(k1, k2) <> distance(k2, k1).
>>
>>That won't be formally a distance, which is required to be symmetric.
>
> Why must it be symmetric? A to B and B to A may be different
> distances if there are one-way routes involved. Or am I missing a
> point?
*formally*
Apparently, it is one of those cases where the
math term and rest-of-the-world word have a
somewhat different interpretation.
Received on Fri Jun 23 2006 - 18:33:56 CDT
