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Re: Canonical DB

From: mAsterdam <mAsterdam_at_vrijdag.org>
Date: Sat, 24 Jun 2006 01:33:56 +0200
Message-ID: <449c79d1$0$31647$e4fe514c@news.xs4all.nl>


Gene Wirchenko wrote:
> Dmitry A. Kazakov wrote:
>

>> mAsterdam wrote:
>>>These requirements establish K as a clean point type.
>>>Aside: With the last condition deleted one can make a
>>>circular K, having distance(k1, k2) <> distance(k2, k1).
>>
>>That won't be formally a distance, which is required to be symmetric.

>
> Why must it be symmetric? A to B and B to A may be different
> distances if there are one-way routes involved. Or am I missing a
> point?

*formally*
Apparently, it is one of those cases where the math term and rest-of-the-world word have a somewhat different interpretation. Received on Fri Jun 23 2006 - 18:33:56 CDT

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