Re: Canonical DB

From: Gene Wirchenko <genew_at_ucantrade.com.NOTHERE>
Date: Fri, 23 Jun 2006 15:51:07 -0700
Message-ID: <ksro92ltturh343l6mh1839fnvif1thjee@4ax.com>

On Fri, 23 Jun 2006 21:59:52 +0200, "Dmitry A. Kazakov" <mailbox_at_dmitry-kazakov.de> wrote:

>On Fri, 23 Jun 2006 15:37:54 +0200, mAsterdam wrote:

[snip]

>> These requirements establish K as a clean point type.
>> Aside: With the last condition deleted one can make a
>> circular K, having distance(k1, k2) <> distance(k2, k1).
>
>That won't be formally a distance, which is required to be symmetric.

Why must it be symmetric? A to B and B to A may be different distances if there are one-way routes involved. Or am I missing a point?

[snip]

Sincerely,

Gene Wirchenko Received on Fri Jun 23 2006 - 17:51:07 CDT