> I have, and it says nothing specific about any individual types, other
> than using them as examples. If you can find a place where the RM
> refers to specific types in defining relational operators, I'd like to
> see you quote it.
>
> - Eric
There is one individual type that *IS* prerequisite to the definition
of RM and/or Relational Algebra, and that's type boolean. Without
boolean, we cannot express/evaluate equality, and without that, we
cannot define JOIN, INTERSECT, MINUS, TCLOSE, the whole damn lot.
Received on Wed Jun 21 2006 - 08:29:47 CDT
