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Re: Example of expression bias?

From: J M Davitt <jdavitt_at_aeneas.net>
Date: Wed, 21 Jun 2006 04:08:18 GMT
Message-ID: <SC3mg.79147$P2.78694@tornado.ohiordc.rr.com>


Tony D wrote:
> J M Davitt wrote:
>

>>CJD calls them type constraints; they define the set of values
>>that constitute the type.  Types are named, so the sets are named.
>>
>>The only thing I'd argue about in Cimode's definition is that
>>operators are part of the data type.  In fact, D+D make the point
>>that the declaration of operators is orthogonal to the declaration
>>of types -- given that the types are extant before the operators.
>>

>
> Before I go, one last point; I'm not sure how the declaration of
> operators can be *completely* orthogonal to type declaration; after
> all, there's not much point in declaring a type if you can't actually
> do anything with it. I understand that not all operators may be defined
> when the data type is first introduced, but at least some operators
> (equivalence definitely) will have to be there pretty much from the
> get-go.

The idea gave me pause, too. They emphasize that operators need not be declared as part of the type declaration. Yes, the RM requires an operator that can distinguish values of given types -- but that operator need not be declared before the type appears in an attribute. The selector operator and the /THE_/ operators are the notable exceptions: they are implicitly declared in the type declaration, IIRC. And, yes, you're right: you can't actually do much with only those. Received on Tue Jun 20 2006 - 23:08:18 CDT

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