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Home -> Community -> Usenet -> comp.databases.theory -> Fraud Number 3: U-Gene
As BB's idiots keep diverting debate to my person, instead of adressing
RM issues I pointed out...I will begin quoting some of their posts to demonstrate their incoherence, ignorance or both...I will let the people judge for themselves...
OK this one's funny...and presents so many confusions I can't count...
This ignorant trully believes that relations = relvalues and asks whether these values have different types thanks to the previous assumption if the relation have different schemas??
SO I tried pointing that out to him...
//Me//
Your question is confusing...
when you ask ...
<<Two relations (relvalues) exists. These relations have different
headers (schemas). Are these relvalues the values of different types?
The tenure of your question seems to indicate you confuse a relvar and its projection as a table....These are 2 different concepts...
..relvars do not have header..header is associated to a projection as a
human need for interpretation. only the body of the table represents a
projection of a relvar...
a relvar can define a type only if it has set of operators associated
to it...(see data type definitions). In case the operators and other
data type prereq are defined... 2 different relvars are necessarily are
possibly defining 2 separate types.
BUT as usual, ignorants persist and sign (always funny seeing them being so sure;))
//U-Gene//
Do you understand the differense between relvalues (I asked about) and
relvar(iables) ? --> This ignorant actually truly believes he can
educate me
//Me// --> gave some extra shot to help him make some sense out of
it...Using sound proofs...I demonstrated his nonsense just
demonstrating the consequence if==of confusing relvalue and
relations...
Given the level of confusion your question implies, I do not believe you are not a position to test my knowledge of difference between relvar and relvalue...
While I had a doubt you meant *relvar* for *relavlue* as a TYPO which would have has sense, I now clearly see you have no clue about what a relation is...Confusing a relvalue, a relation and its projection as table...
Here's the proof...
You state...
<<Two relations (relvalues) exists.>>
Your question implies relations = relvalues...which if I follow this
false premise reasonning would lead to relations that have similar
relvalues being equal which is totally false...2 relvar with same
relvalues are NOT necessarily equal.
<<These relations have different
headers (schemas). Are these relvalues the values of different >>
This question is totally irrelevant if you consider a relation as being
equal to a relvalue...
I rest my case...and let people judge from themselves.... Received on Sat Jun 17 2006 - 15:06:54 CDT
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